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26 Nov 2019

Consider the Cartesian plane below, with the three charges arrangedas follows:
+2Q@(0,+a) +2Q@(0,-a) -Q@(+a,0)


a)Derive a formula for the electric potential on the positivex-axis at x>a as a
function of x. Let electric potential equal zero at infinity.

b) Explain how this formula could be used to find a positive atwhich the electric

field is zero.
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O+2Q at y=+a
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-------------------------------------O-------------------------------
| -Q at x=+a
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O+2Q at y=-a
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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

Related questions


A charge q is at the origin, and a charge -2q is on the positivex-axis at x = a. A point (not at infinity) on the x-axis where theelectric field is zero could be found in the region

a) x < 0
b) 0 < x < a
c) x > a
d) no place
e) in all of the regions a, b, and c

please explain how you get the answer, thank you


consider three point particles lying along the x axisseparatedby a distance d, as shown. These particles have charges-Q, +2Q, and-Q respectively. Note that the z axis is comingstraight up out ofthe paper from the location of the positivepoint charge.
(a) Calculate the electrostatic potential (y,.z) producedbythese charges at the arbitrary point [0,y,z] in the yzplane.
(b) Use your answer from part (a) along with asymmetryargument to calculate E (electric field) at the samearbitrarypoint. [ Note that if you like, you can check your answersfor E byusging the principle of superposition and the firld createdby apoint charge.

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