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23 Nov 2019
A wire of 58.0-cm length and 14.0-g mass crosses a uniform magnetic field of 435 mT. Both the wire and the magnetic field lie in a horizontal plane, making an angle of 60.0° with respect to each other, as depicted in the figure on page 1 of this handout. What is the minimum current (in mA) in the wire required to magnetically levitate the wire, i.e., so that the magnetic force on the wire exactly balances its weight?
A wire of 58.0-cm length and 14.0-g mass crosses a uniform magnetic field of 435 mT. Both the wire and the magnetic field lie in a horizontal plane, making an angle of 60.0° with respect to each other, as depicted in the figure on page 1 of this handout. What is the minimum current (in mA) in the wire required to magnetically levitate the wire, i.e., so that the magnetic force on the wire exactly balances its weight?
Trinidad TremblayLv2
23 Nov 2019