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23 Nov 2019
Figure 28-50 shows a wood cylinder of mass m = 0.211 kg and lengthL = 0.0772 m, with N = 15.0 turns of wire wrapped around itlongitudinally, so that the plane of the wire coil contains thelong central axis of the cylinder. The cylinder is released on aplane inclined at an angle ? to the horizontal, with the plane ofthe coil parallel to the incline plane. If there is a verticaluniform magnetic field of magnitude 0.627 T, what is the leastcurrent i (in A) through the coil that keeps the cylinder fromrolling down the plane?
its chapter 28 problem 53 in the fundamentals of physics 8ebook.
i'm just not getting how they found A=2rL and not 2prL.. everythingelse i get.
Figure 28-50 shows a wood cylinder of mass m = 0.211 kg and lengthL = 0.0772 m, with N = 15.0 turns of wire wrapped around itlongitudinally, so that the plane of the wire coil contains thelong central axis of the cylinder. The cylinder is released on aplane inclined at an angle ? to the horizontal, with the plane ofthe coil parallel to the incline plane. If there is a verticaluniform magnetic field of magnitude 0.627 T, what is the leastcurrent i (in A) through the coil that keeps the cylinder fromrolling down the plane?
its chapter 28 problem 53 in the fundamentals of physics 8ebook.
i'm just not getting how they found A=2rL and not 2prL.. everythingelse i get.
Nestor RutherfordLv2
31 Mar 2019
