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23 Nov 2019

At a distance 9.8×10-3 m from a certain point charge the magnitude of the electric field produced by the charge is 3.6 N/C and the field is directed toward the charge. Find the charge, including its sign.

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Lelia Lubowitz
Lelia LubowitzLv2
11 May 2019

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Related textbook solutions

Physics: Principles with Applications
7th Edition, 2013
Giancoli
ISBN: 9780321625922

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The Earth has a net electric charge that causes a field at a point near its surface equal to 150 N/C and directed in toward the center of the earth. What magnitude and sign of charge would a 60 kg human have to acquire to overcome his or her weight by the force exerted by the Earth's electric field.
 

A point charge q = +40.0 μC moves from A to B separated by a distance d = 0.180 m in the presence of an external electric field of magnitude 275 N/C directed toward the right as in Figure P16.16. Find (a) the electric force exerted on the charge, (b) the work done by the electric force, (c) the change in the electric potential energy of the charge, and (d) the potential difference between A and B.  

A total charge Q = 3.6 μC is distributed uniformly over aquarter circle arc of radius a = 8.8 cm as shown.



a)What is λ the linear charge density along the arc?

b)What is Ex, the value of the x-component of theelectric field at the origin (x,y) = (0,0) ?

c)What is Ey, the value of the y-component of theelectric field at the origin (x,y) = (0,0) ?

d) How does the magnitude of the electric field at the originfor the quarter-circle arc you have just calculated comnpare to theelectric field at the origin produced by a point charge Q = 3.6 μClocated a distance a = 8.8 cm from the origin along a45o line as shown in the figure?

A. The magnitude ofthe field from the point charge is less than that from thequarter-arc of charge.
B. The magnitude of thefield from the point charge is equal to that from the quarter-arcof charge
C. The magnitude of thefield from the point charge is greater than that from thequarter-arc of charge


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