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23 Nov 2019

The data below indicated how much solar radiation is availableaveraged over a month for Eugene Oregon and Bend Oregon. The unitsare KWH per square meter per day.

So, for example, we see that in March there are 3.8 KWH per squaremeter per day. Therefore if we had 100 square meters we wouldreceive 3.8 x 100 x 30 (days per month) 11400 KWH of energy overthat month. But, we have to factor in PV panel efficiency and if weassume it to be 10% in this case then our output is 1140 KWHs ofenergy for that month.

Using this procedure combined with the data below, approximatelyhow big of PV array (in units of square kilometers) would be neededin order to power Eugene for a year if you built it in Eugenecompared to if you built it in Bend.

To do this you need to sum up all the individual months output foryour array size. Show all work.

The target number your trying to reach with the output of your PVarray is an annual output of 3 Billion KWHs.

Note: this problem is not difficult - its easy to setup in aspreadsheet. Your guessing at the size of the array - so pick asize, determine each month's yield for that size (e.g. at 100meters the March yield in eugene is 1140 KWHs) and sum up the 12months can compare that the target value of 3 Billion KWHs. If yourless than that, you need a bigger array.

Finally, at a cost of 400$ per square meter what is the total costof your array in Eugene and your array in Bend?



City JAN FEB MAR APR MAY JUN JUL AUG SEP OCT NOV DEC
Eugene 2.0 2.7 3.8 4.7 5.3 5.5 6.2 6.0 5.5 3.8 2.1 1.6
Bend 3.0 3.8 4.9 5.7 6.2 6.4 7.0 6.9 6.4 5.1 3.2 2.7

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