(1) Using Equation delta.d = 2do+ n glass d glass - d1 and Figure 1-3 and 1-4 located in theExperimental Procedure, determine the speed of light assuming that the distancebetween the transmitter-side mirror and the face of the corner-cube do is1.7m and the distance between the two mirrors d1 is 4 em. (Note: The corner-cubeis designed so that light always travels 6.7 em within the corner-cube- i.e. dglass)). nglass=1.5 (2) Calculate the time-of-flight you expect for light to propagatea distance of 20 m in (a) vacuum and (b) a medium with an index of refraction n =1.5. Express your answer in nanoseconds (ns). (3) In telephone calls using a satellite, you sometimes can hear adelay in the response of the other person. Satellites are usually either inlow-Earth orbit Uust above the atmosphere) or much higher in geosynchronous orbit.The latter is at an altitude of 35,785 kilometers (22,236 miles), wherethe satellite completes one orbit in exactly one day. Because the orbitalvelocity matches the spin rate of the Earth, a satellite in a circular equatorialgeosynchronous orbit appears to hover motionless over a single location on theequator. The total delay in hearing your correspondent's reply, due to thefinite speed of light, is due to two round trips. If you and your correspondentwere located nearby, and on the equator, the only distance involved is thedistance from you to the satellite, the total distance corresponding to the delayis 4 x 35,785 km. Calculate this delay, assuming the radio signal travels at thespeed of light in a vacuum. Report your answer in units of seconds, anddiscuss in one sentence whether this delay is long enough for you to notice.Identify at least one factor that could cause the actual delay to be longer than whatyou calculated.
