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12 Nov 2019

1. A projectile launched vertically from the surface of the Moonrise to an altitud of 365 km . What was the projectile's initialspeed?
I got to do it by Conservation of Energy! Please step by step, forme to undertand!!
If anyone know the book with this exercises please tell me...
E_i = E_f
K_i + U_i = (K_f = 0) + U_f
1/2V^2 + (- GM/R) = (-GM/(R +h))
"Anyone that could continue this and give me the correct answer, orif I'm wrong tell me what's wrong."

2. If a projectiles is launched vertically from the Earth with aspeed equal to the escape speed, how high above the Earth's surfaceis it when its speed is half the escape speed? Again: E_i =E_f
K_i + U_i = K_f + U_f
1/2(V_esc^2) - (GM/R) = 1/2(V_esc/2)^2 - (GM/R+h).....

3. A projectile is launched vertically from the surface of the Moonwith an initial speed of 1050 m/s. At what altitude is theprojectile's speed one-haif its initial value?
I know that the answert is h=3 x 10^5 m, but howI get it??
E_i =E_f ....



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Nestor Rutherford
Nestor RutherfordLv2
6 Aug 2019
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