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A conducting solid sphere (R = 0.281 m, q =  ) is shown in the figure. Using Gauss's Law and two different Gaussian surfaces, determine the electric field (magnitude and direction) at point A, which is 0.00000100 m outside the conducting sphere. (Hint: One Gaussian surface is a sphere, and the other is a small right cylinder.)

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Vikas
VikasLv10
1 Feb 2019

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