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4 Jan 2022
Problem 66
Page 406
Section 7.1: Integration by Parts
Chapter 7: Techniques of Integration
Textbook ExpertVerified Tutor
4 Jan 2022
Given information
The given equation is 
Step-by-step explanation
Step 1.
Let 
i.e 
then 
and 
Thus the above integral changes to
According to Equation 6, the reduction formula for 
is
so,
Now from previous exercise we got that
so,
And so the above integral changes to
Substituting
back again from the main integral, we get
back again from the main integral, we get
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CALCULUS:EARLY TRANSCENDENTALS
4 Edition,
Rogawski
ISBN: 9781319050740
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