A battery has an emf of 12.0 V and an internal resistance of 0.15 . What is the terminal voltage when the battery is connected to a 1.60 resistor?

answers

watching

views

For unlimited access to Homework Help, a Homework+ subscription is required.

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

jdhasnaaLv4

25 Apr 2023

Unlock all answers

Get 1 free homework help answer.

Get unlimited access

Already have an account? Log in

You have 0 free answers left.
Get unlimited access to 3.8 million step-by-step answers.

Get unlimited access

Already have an account? Log in

Casey DurganLv2

16 Dec 2019

Get unlimited access

Already have an account? Log in

Related questions

A real battery is not just an emf, we can model a real 1.5V battery as a 1.5 V emf in series with a resistor known as the internal resistance. A typical battery has 1.0 Ω internal resistance due to imperfections that limit the current through the battery. When there's no current through the battery, and thus no voltage drop across the internal resistance, the potential difference between its terminals is 1.5 V, the value of the emf. Suppose the terminals of this battery are connected to a 3 Ω resistor.

what fraction of the battery's power is dissipated by the internal resistance?

violeteel500

1. The emf and the internal resistance of a battery are shown in the figure. If a current of 8.3 A is drawn from the battery when a resistor R is connected across the terminals ab of the battery. What is the power dissipated by the resistor R?

2. The emf and the internal resistance of a battery are shown in the figure. When the terminal voltage V_ ab is equal to 17.4V, what is the current through the battery, including its direction?