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23 Nov 2019

Find a scalar x for which xv + w is parallel to u where v = 2i -j,w = -3i + 4j, and u = 9i + 3j

so i have

x(2i-j) + (-3i+4j) = 9i + 3j

isolated the i's and j's i get

(2x - 3)i - (x - 4)j = 9i + 3j

i add the variable k to the 9i + 3j because according to mynotes(to vectors are parallel if a = xb for some scalar x)

so now i have

9k = 2x - 3
3k = -x + 4

multiply the bottom equation by 3, eliminate the k so that i get x=3

but when i check my answer to see if

(3)(2i - j) + (-3i + 4j) = 9i + 3j itdoesn'twork....................

so i think i'm doing this wrong, any help?? =(

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