1
answer
0
watching
629
views
13 Dec 2019
3. Calculate the equilibrium constant for the reaction: CN- + H2O == HCN + OH- A.)5.0*10^-4 B.) 5.0*10^-5 C.) 2.0*10^-5 D.) 2.0*10^-4 E.) 4.9*10^-10
Ka Values: HF, 6.8*10^-4 HNO2, 4.5*10^-4 HOBr, 2.5*10^-9 NH4+, 5.6*10^-10 HCN, 4.9*10^-10
3. Calculate the equilibrium constant for the reaction: CN- + H2O == HCN + OH- A.)5.0*10^-4 B.) 5.0*10^-5 C.) 2.0*10^-5 D.) 2.0*10^-4 E.) 4.9*10^-10
Ka Values: HF, 6.8*10^-4 HNO2, 4.5*10^-4 HOBr, 2.5*10^-9 NH4+, 5.6*10^-10 HCN, 4.9*10^-10
Lelia LubowitzLv2
17 Dec 2019
Related textbook solutions
Basic Chemistry
5 Edition,
Timberlake
ISBN: 9780134138046
Principles of Chemistry Molecular Approach
4th Edition,
Tro
ISBN: 9780134112831
Principles of Chemistry Molecular Approach
3rd Edition, 2014
Tro
ISBN: 9780321971944
Chemistry: Structure and Properties
2nd Edition,
Tro
ISBN: 9780134293936
Chemistry: A Molecular Approach
3rd Edition,
Tro
ISBN: 9780321809247
Chemistry: A Molecular Approach
5th Edition,
Tro
ISBN: 9780134874371
Principles of Chemistry: A Molecular Approach
4th Edition,
Tro
ISBN: 9780134895741
Chemistry: The Central Science
14th Edition, 2017
Brown
ISBN: 9780134414232
Related questions
Given the following acids and Ka values:
| HClO4 | HOAc | HCN | HF |
| 1 x 107 | 1.76 x 10-5 | 4.93 x 10-10 | 3.53 x 10-4 |
What is the order of increasing base strength?
a. CN-, ClO4-, F-, OAc-
b. ClO4-, OAc-, CN-, F-
c. CN-, F-, OAc-, ClO4-,
d. ClO4-, F-, OAc-, CN-
e. CN-,OAc-, F-, ClO4-
