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12 Dec 2019
A sample of a substance with the empirical formula XBr3 weighs 0.5724 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.1056 g. The chemical reaction is
XBr3 + 3 AgNO3 -----------> 3AgBr + X(NO3)3
(a) Calculate the formula mass of XBr3.
Formula mass XBr3 = g mol-1
(b) Calculate the atomic mass of X.
Atomic mass X = g mol-1
A sample of a substance with the empirical formula XBr3 weighs 0.5724 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.1056 g. The chemical reaction is
XBr3 + 3 AgNO3 -----------> 3AgBr + X(NO3)3
(a) Calculate the formula mass of XBr3.
Formula mass XBr3 = g mol-1
(b) Calculate the atomic mass of X.
Atomic mass X = g mol-1
Hubert KochLv2
13 Dec 2019
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