A sample of a substance with the empirical formula XBr2 weighs 0.5674 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 0.9542 g. The chemical reaction is

XBr2 + 2 AgNO32AgBr + X(NO3)2

(a) Calculate the formula mass of XBr2.

Formula mass

XBr2 = g mol-1

(b) Calculate the atomic mass of X.

Atomic mass

X = g mol-1

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Nestor RutherfordLv2

23 Mar 2019

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Related questions

A sample of a substance with the empirical formula XBr₃ weighs 0.5724 g. When it is dissolved in water and all its bromine is converted to insoluble AgBr by addition of an excess of silver nitrate, the mass of the resulting AgBr is found to be 1.1056 g. The chemical reaction is

XBr₃ + 3 AgNO_{3 ----------->} 3AgBr + X(NO₃)₃

(a) Calculate the formula mass of XBr₃.

Formula mass XBr₃ = g mol^-1

(b) Calculate the atomic mass of X.

Atomic mass X = g mol^-1