PHYS 1000 Lecture Notes - Lecture 1: Short Circuit, V12 Engine, Internal Resistance

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petahgriff69

26 Feb 2023

School

Georgia Tech

Department

Physics

Course

PHYS 1000

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Ch 28 problem set solution: 43, 45, 52, 54, 60, 66, 73, 83. You have a 2. 0 resistor, a 3. 0 resistor, a 6. 0 resistor, and a 6. 0 v battery. Arrange all three resistors on a diagram to make a circuit in which the battery delivers 9. 0 w of power. Solve: we can find the equivalent resistance necessary for the battery to deliver 9 w of power: 3. 0 series totals 4. 0 equivalent resistance. and 6. 0. Parallel combination has an equivalent resistance of 2. 0. Resistors that make 4. 0 is shown in the figure above. , which when added to the 2. 0 resistor in. Model: use the laws of series and parallel resistances. Solve: despite the diagonal orientation of the 12 resistor, the 6 have a common connection at both the top end and at the bottom end. The trickiest issue is the 10 resistor.

Related Questions

The power P delivered to each resistor is the product of thecurrent squared (I^2) and the corresponding resistance R, or P =I^2*R. The resistances are known, and Ohm's law can be used to findthe current. Ohm's law states that the current in the circuit(which is also the current through each of the resistors) equalsthe voltage V of the battery divided by the equivalent resistanceRs of the two resistors: I = V/Rs. Since the resistors areconnected in series, we can obtain the equivalent resistance byadding the resistances.

Three resistors, 3 O, 4.5 O, and 5.5 O, are connected in seriesacross a 12-V battery. Find the power delivered to eachresistor.

An ideal voltmeter connected across a certain 9-V fresh battery reads 9.30 V, and an ideal ammeter briefly connected across the same battery reads 3.70 A. We say the battery has an open-circuit voltage of 9.30 V and a short-circuit current of 3.70 A. Model the battery as a source of emf ε in series with an internal resistance r. Determine both (a) ε and (b) r. An experimenter connects two of these identical batteries together as shown in the figure below. Find (c) the open-circuit voltage and (d) the short-circuit current of the pair of connected batteries. (e) The experimenter connects a 12.0-Ω resistor between the exposed terminals of the connected batteries Find the current in the resistor. (f) Find the power delivered to the resistor. (g) The experimenter connects a second identical resistor in parallel with the first. Find the power delivered to each resistor. (h) Because the same pair of batteries is connected across both resistors as was connected across the single resistor, why is the power in part (g) not the same as that in part (f)?

apricotleopard426

A circuit consisting of 5 resistors is shown in the graph. Their resistances are R1 = 17 Ω, R2 = 35 Ω, R3 = 86 Ω, R4 = 32 Ω, and R5 = 29 Ω, and the emf of the battery is ε = 5.5 V. Suppose the internal resistance of the battery is zero.

Express the equivalent resistance of the combination of R2, R3, and R4.
Calculate the numerical value of the total resistance R in Ω.
Express the current I through R1 in terms of the emf ε and the equivalent resistance R.
Calculate the numerical value of I in A.
Express the power P dissipated by R₁ through I and R₁.
Calculate the numerical value of the power P in W.

tealweasel435

PHYS 1000 Lecture Notes - Lecture 1: Short Circuit, V12 Engine, Internal Resistance

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