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STATS 250 Lecture Notes - Lecture 12: Standard Deviation, Confidence Interval

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School
U of M
Department
Statistics
Course
STATS 250
Professor
Nadiya Fink

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STATS 250 verified notes
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11

STATS 250 Lecture Notes - Lecture 11: Sampling Distribution, Binomial Distribution, Statistical Parameter

12

STATS 250 Lecture Notes - Lecture 12: Standard Deviation, Confidence Interval

13

STATS 250 Lecture Notes - Lecture 13: Dependent And Independent Variables, Test Statistic, Pie Chart

Document Summary

=0. 60: give the standard error for the estimate in part (a) and use it to complete the sentence that interprets the standard error in terms of an average distance. = 0. 6(cid:4666)1 0. 6(cid:4667) (2) we would estimate the average distance between the (1) s. e. 0. 0219 possible values and p to be about 0. 0219. 1 p + is a 95% ci for p. P 1: when we construct a ci for p, we don"t know whether it does or doesn"t contain true p. it either does or it doesn"t. 2 (cid:4666)1 (cid:4667: thus, about 95% of the intervals 2 (cid:4666)1 (cid:4667) will contain population proportion p, example, in a gallup youth survey n = 500 randomly selected american teenagers were asked about how well they get along with their parents. One survey result was that 270 of the 500 sampled teens said they get along very. Well with their parents: the sample proportion was found to be 270/500 = 0. 54.

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Related textbook solutions

Introductory Statistics
OER Edition, 2013
Openstax
ISBN: 9781938168208

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Related Questions

. SAT scores are distributed with a mean of 1,500 and a standard deviation of 300. You are interested in estimating the average SAT score of first-year students at your college. If you would like to limit the margin of error of your 95% confidence interval to 25 points, how many students should you sample? Make sure to give a whole number answer

2. We wish to estimate what percent of adult residents in a certain county are parents. Out of 600 adult residents sampled, 354 had kids. Based on this, construct a 95% confidence interval for the proportion, p, of adult residents who are parents in this county.
Give your answers as decimals, to three places.

Use the following scenario for questions 6 – 8. In 2016-17, the average SAT score of the UVA first year class was 1420 out of 1600. An advisor in the statistics department is interested in determining whether statistics majors from that class have higher SAT scores than the average. He tests H,:µ = 1420 against Hạ: µ > 1420, where u is the mean SAT score for statistics majors from the 2016-17 first year class. In a simple random sample of 30 statistics majors, he finds a sample mean SAT score of 1440 with sample standard deviation of 40.

6. What is the value of the test statistic for this significance test?

a. 0.09

b. 0.5

c. 2.73

d. 20

7. From what distribution is this test statistic?

a. N(0, 1)

b. N(1420, 7.30)

c. t distribution with 29 degrees of freedom

d. t distribution with 28 degrees of freedom

8.) The p-value for this test is 0.005. Which of the following is a proper interpretation of this p- value?

a.There is a 0.5% chance that the null hypothesis is true.

b. If the population mean SAT score really is 1420, there's a 0.5% chance that the sample a. mean SAT score from 30 statistics majors would equal 1440.

c.If the population mean SAT score really is 1420, there's a 0.5% chance that the sample mean SAT score from 30 statistics majors would be 1440 or lower.

d. If the population mean SAT score really is 1420, there's a 0.5% chance that the sample mean SAT score from 30 statistics majors would be 1440 or higher.