STAT 1000Q Lecture 15: Week 8 Cornell-style Notes [TYPED]
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Stat 1000q lecture 15 - point/interval estimation and confidence. Calculating the population proportion for a speci c characteristic. P = x n p. Q = 1 - (x/n) = (n - x)/n. N(1 - p) = nq 15. So we know how to calculate a population proportion, but now we want to calculate that value for a speci c characteristic. Steps: we have access to all n members of the population, survey the entire population, determine the number of members x that have the speci c characteristic of interest, p = x n. 1 - p = q = the number of members of the sample without the characteristic of interest. q = 1 - (x/n) = (n - x)/n. Determining the shape of the sampling distribution of p . Under certain conditions, the sampling distribution of p is approximately normal. If np 15 and n(1 - p) = nq 15:
