PHYS 1501Q Lecture Notes - Lecture 43: Thermal Conductivity, Thermal Conduction, Black Body

40 views4 pages
Verified Note

Document Summary

Physics 1501q - lecture 43 - thermal physics: heat transfer . Whenever there is a temperature difference, heat transfer occurs. : heat transfer through stationary matter by physical contact. The transfer can be viewed on a microscopic scale: It is an exchange of energy between particles oscillating around their equilibrium position due to collision. Less energetic particles gain energy during collisions with more energetic particles. H = q/t = ka(dt/dx) = ka( t/ x) k = thermal conductivity (w/km) (source: slide 9 of 12/3 lecture slides) Example problem: heat loss through walls of a house with/without fiberglass insulators. Consider that the total area of the walls is 200 m 2 , the thickness of the wall is 15 cm, the temperature inside the house is 20 c, and the temperature outside is 0 c. Find the difference in the electricity cost in one day with/without fiberglass insulator. sh. 15/kwh. (find k values using a given chart).

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related textbook solutions

Related Documents