Calculus 1000A/B Lecture Notes - Lecture 34: Mean Value Theorem, Antiderivative

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Calculus 1000a lecture 34 section 4. 9 antiderivatives. Midterm marks have been sent out- check owl or school email; quiz 3 available for pickup. We can start by introducing the definition of antiderivatives: A function f is called an antiderivative of f on an interval i if f(cid:859)(cid:894)x(cid:895)= f(cid:894)x(cid:895) for all (cid:858)x(cid:859) in the interval i. Let"s look at a simple example: based on this definition, we know that we will be looking for a power function of order three. Example 1: (cid:1858)(cid:4666)(cid:4667)=(cid:2870) find the antiderivative f check that f(cid:859)(cid:894)x(cid:895)= x2= f(x: recall = (cid:2869, (cid:4666)(cid:3119)(cid:4667) =(cid:885)(cid:2870) (cid:4672)(cid:3119)(cid:2871)(cid:4673)=(cid:2869)(cid:2871)(cid:885)(cid:2870)=(cid:2870, therefore, we could say that the antiderivative is (cid:4666)(cid:4667)=(cid:3119)(cid:2871) For example, we could write (cid:4666)(cid:4667)=(cid:3119)(cid:2871)+(cid:1855), as we know that the derivative of a constant is zero. We have found an antiderivative, but how would we know if there are other antiderivatives that satisfy have various theorems to help us answer this question: now, we need to get the coefficient to be 1.

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