CEM 142 Chapter 17.3-17.6: Ch 17.3-17.6 Practice Problems
15060mL of 0.25M Hbr titrete w10,5014
KOH Cale PH after add 30mL KOH
LMMy 60 2000 0060 L
L30mL11000 I0030 L
nML
Nof Hbr 0.25M x0.060L
i0.015 mol HBr
naf KOHE 0.5014 x0.030
z0.015moles Naott
HBrt KOH 7Hao KBR
0.015mm 0.015mol
0.0 0µmol I0.815mL
Q
5acid sbese cancel art
pH 27,0 became Kbr hes my
titty effect in 90mL ofHao
KO Titration 50mL 2014kHz Ks 1.8 10 5
with 0.20M HNOz Cdc pH after adding
50mL of titrent
50mL 0.050L
nof NH 0.20M x0.050L
0.01 mole NHS yd lequal
O.O mo Mlb due to equal
nEHN03 0.2014 0,0504 parts Ran
0.01 mol NHz has two
NHz tHNO NHy No ports
NH4ttHz0q5 NHz HzOt
ka lHtKN pH putlog Fifa
NHI
ka Kb kw 14
Ka ke 1855.56 15
Kb
pKa log 5.56 10
pka 9.26
Concentration NHyt 00.10M
0.1 L
Ht TEAM
HE 7.46 10 6
pHs log 7.46 10 6
5,13
30mL of 0.5014 ctbcoottlkazl.sk ot
titretrew o.sromNaoH.CdcpHoftr
111rem wld 4Na
adding 30mL Nao H
nof dHzC00H 0.50M x0.030L
0.015
mole
nifMaOtt 0.50M x0.030L
i0.015M
NaOH tCHgcoott CH COO Nat 420
CH COO tThos CH COOHOH
o
015 015
00 TEE
Concert CHgCOOH0.015
Fe 0.25M
Kye tycoon Ott HCoo
4110
155.56 10 0
OH tF
Otto 1.18 10 5
y
