A bullet of mass m is fired with speed v0 toward a steel block of mass M which is hanging from a massless rod of length D. After a very short impact, the bullet bounces backward with the speed vf while the block swings up to a height h. The collision is not elastic. Treat both bullet and block as point particles (point masses). What is the rotational inertia of the block relative to point P, in terms of M, D, and numerical constants as needed. What is the angular momentum of the bullet relative to point P after the impact, in terms of m, vf, D, and numerical constants as needed. What is the angular speed omega f of the block after the impact, in terms of v0, vf, D, m, M, and numerical constants as needed. How high the block swings after the impact, in terms of M, D, wf, and numerical constants as needed. Answers: I = MD2, L = mDvf(-i), omega)f = m(v0 + vf)/MD h = (D omega f)2/2g. The answers are provided. Help me figure out this problem?