OCS 1005 Chapter : OCS ASSGN 3

9 views1 pages

Document Summary

Question 1: how much heat would be required to heat 1 gram of pure liquid water from. Email: cparis5@lsu. edu degrees celsius would be 10 calories. Answer: 1 gram raised 1 degree celsius = 1 calorie. So 10 grams raised by 5 would give you 5 x 10, which in turn gives you your answer of 50 calories. Answer: heat required to melt ice = 3 grams x 80 calories/gram = 240 calories. Answer: you use the formula 2 grams x 540 cal/gram = 1080 calories. Answer: the melting energy of ice is 80 calories/gram so you do 80 x 3 and get: then you multiply 3 x 10 and get 30.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents