ME 2334 Chapter : Chapter 11 Notes
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Mass: mtot = m1 + m2 + + mn = mi ntot = n1 + n2 + + nn = ni. Mass fraction (concentration): ci = mi /mtot ; Mole fraction (concentration): yi = ni /ntot ; Mixture variables: as ci = 1 there are n 1 variables to fix composition mi = mi ni ; mi is molecular mass of component i . Conversion between mass and mole basis ci = mi mtot ni mi / ntot. Yj mj yi = ni ntot mi / (mi mtot) Mj / (mj mtot) ci / mi. Assume we start with the mass fractions known. Solution _____________________________________________ (cid:149) gas mixtures (cid:149) gas vapor mixtures, moist air (cid:149) energy equation moist air (cid:149) adiabatic saturation (cid:149) psychrometric chart. A mixture is given by 12% carbon dioxide, 4% oxygen, 82% nitrogen and 2% carbon monoxide on a mole basis. Determine the mass fractions and the mixture molecular mass.
