EE 2950 Chapter : Chapter 17
Document Summary
B gap tki a cos( tki b cos( Using the expressions given in the exercise statement for the currents, we have. Then using the identity for the products of cosines, we obtain cos( However we can write cos( t cos( t. Ki m cos( t which can be recognized as flux pattern that rotates clockwise. E17. 2 at 60 hz, synchronous speed for a four-pole machine is: ns f. This corresponds to a speed of 1775 rpm. E17. 3 following the solution to example 17. 1, we have: For a delta-connected machine, the magnitude of the line current is. A 68. 27 rms and the input power is. E17. 4 the equivalent circuit is: jxrz eq eq eq j j. A rms and for a delta connection, the line current is. The power crossing the air gap is (three times) the power delivered to the right of the dashed line in the equivalent circuit shown earlier. sirp ag 3 kw 95. 49 starting.
