EE 2950 Chapter : Chapter 13 HW

11 views34 pages
15 Mar 2019
School
Course
Professor

Document Summary

E13. 1 the emitter current is given by the shockley equation: Solving for bev , we have vvv ln. E13. 4 the base current is given by equation 13. 8: i. 1 which can be plotted to obtain the input characteristic shown in figure. For the output characteristic, we have provided that i. The output characteristics are shown in figure 13. 6b. As shown on the output load line, we find. E13. 6 the load lines for the new values are shown: As shown on the output load line, we have: 0. 3. E13. 7 refer to the characteristics shown in figure 13. 7 in the book. Bc ii point in the active region of the output characteristics. Then we write a kcl equation for the output circuit: V 3. 8 (b) inspecting the load lines, we see that the maximum of vin corresponds to ibmin which in turn corresponds to vcemin. Because the maximum of vin corresponds to minimum vce, the amplifier is inverting.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers
Class+
$30 USD/m
Billed monthly
Class+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
7 Verified Answers

Related Documents

Related Questions