EE 2950 Chapter : Chapter 13
Document Summary
E13. 1 the emitter current is given by the shockley equation: Solving for bev , we have vvv ln. E13. 4 the base current is given by equation 13. 8: i. 1 which can be plotted to obtain the input characteristic shown in figure. For the output characteristic, we have provided that i. The output characteristics are shown in figure 13. 6b. As shown on the output load line, we find. E13. 6 the load lines for the new values are shown: As shown on the output load line, we have: 0. 3. E13. 7 refer to the characteristics shown in figure 13. 7 in the book. Bc ii point in the active region of the output characteristics. Then we write a kcl equation for the output circuit: V 3. 8 (b) inspecting the load lines, we see that the maximum of vin corresponds to ibmin which in turn corresponds to vcemin. Because the maximum of vin corresponds to minimum vce, the amplifier is inverting.