CHEM 142 Chapter Notes - Chapter 21: Buffer Solution, Equivalence Point, Sodium Acetate

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Chapter 18: added oh- will react almost stoichiometrically (1:1) with a weak acid ha to form a- and. H2o: added h3o+ will react almost stoichiometrically (1:1) with a weak base a- to form ha and. If a solution contains both ha and a- then most added acid or base will be neutralized- called a buffer because it is resistant to large changes in ph- as long as the amount of. Henderson-hasselbalch: how many moles of hno3 should be added to 1. 0 l of a 0. 20 m solution of nach3coo (sodium acetate) to yield a buffer with a ph of 5. 0, given, equal to the ka of acetic acid. [h3o+] = 1. 0 x 10-5: henderson-hasselbalch: 5. 0 = -log(1. 75 x 10-5) + log( 0. 2 , ka = 1. 75 x 10-5 = [3+][ ] => 1. 75 x 10-5 = (1. 0 x 10-5) [ ] [ha] = x, [a-] = 0. 2-x x = 0. 2/1. 75.

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