MATH 302 Chapter 1: Basic theorem and proof
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If the range of the values of x is from {i to j} and p (x(i)) = f (x(i)) The first part of the proof consists of proving that f(x(i)) = p(x(i)). This comes from realizing that for all x< i, p(x) = 0 and hence f(x) = 0. Hence, f(x(i)) = p(x(i)) + p(x < i) P(xi) + p(xi) = 1 f(x(i), p(x
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