ACTSC231 Chapter 2: Chapter_2_solutions_-_Theory_and_Practice20120913_5051d25ff0926.pdf

• School: University of Waterloo
• Department: Actuarial Science
• Course: ACTSC231
• Professor: Keith Freeland

Document Summary

X = 1000(1. 02)4 +1500(1. 02) 4 = 1082. 43 +1385. 77 = . 20: a) b) c) Y (1. 0025)48 = z 1508. 69(1. 0025)48 = . 79: at the end of 7 years: x +1000(1. 035)8 = 2000(1. 035) 2. X = . 21: x = 4000(1. 015)12 1000(1. 015)8 2000(1. 015)4. = 4782. 47 1126. 49 2122. 73 = . 25: x = 1200(1. 015)12 500(1. 015)6 = 1434. 74 546. 72 = . 02, at the end of 4 years: X + x(1. 03)2 +1200(1. 03)4 + 900(1. 03)7 = 3000(1. 03)9. X = . 89: balance on september 1,2011: = 3800. 01 1074. 65 1311. 27 954. 81 = . 58: x = 200(1. 03)4 +150(1. 03)3 250(1. 03)2 100(1. 03) = 225. 10 163. 91 265. 23 +103 = . 78: at the end of 3 years: X = . 61: at the time of the man"s death: 42: x(1. 006)9 + 2x(1. 006)5 + 2x = 4000(1. 006)12. X = . 04: maturity value of original debt: X = . 32: a) x = 500[1+ (0. 07)( = 488. 60 + 665. 08 = . 68: x = 500[1+ (0. 07)( = 505. 83 + 687. 96 = . 79: x = 500[1+ (0. 07)(