PHYS130 Chapter Notes - Chapter 6: Friction, Centripetal Force, Rna

<p>An 1100-kg car accelerates from 0 to 30 m/sec in 12 sec.&#160; If a frictional force of 200 N opposes the motion, what forces must the wheels exert backward on the pavement to cause this acceleration?</p>

A 1200 kg car is being driven up a 5.0? hill. The frictional force is directed opposite to the motion of the car and has a magnitude of f = 524 N. A force F? is applied to the car by the road and propels the car forward. In addition to these two forces, two other forces act on the car: its weight W? and the normal force F?N directed perpendicular to the road surface. The length of the road up the hill is 290 m. What should be the magnitude of F?, so that the net work done by all the forces acting on the car is 150 kJ?

A Mercedes-Benz 300SL (m = 1900 kg) is parked on a road that rises10° above the horizontal.
(a) What is the magnitude of the normal force?
_______ N

(b) What is the static frictional force that the ground exerts onthe tires?
_________N

Section 4.8 The Normal Force
Section 4.9 Static and Kinetic Frictional Forces