STAT 571 Final: STAT 571 UW Madison Fall 00Final Solutions
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H0 : p = 0. 5 for each comparison. Comparison- wise: for yred b(6, p), p-value = 2 p (yred : = 0. 031; for yblue b(9, p), p-value = 2 [p (yblue = 8) + p (yblue = 9)] = 0. 039; for. Ygreen b(40, p), yn a n (20, 10) under h0 and p-value = 2 p (yn a 12) = 2 p (z . The re- sults are 0. 093, 0. 117, 0. 033 for the red, blue, and green coin. Hence reject h0 at the 5% level only for the green coin: h0 : = 1. 5 vs. ha : 6= 1. 5. By clt, z = ( y 1. 5)/s y n (0, 1) under h0 : = 1. 5. 200 (70 1 + 80 2 + 50 3) = 1. 9 and s2 = 1. 199 [70 (1 1. 9)2 + 80 (2 1. 9)2 + Hence, there is very strong evidence against h0. 2. (a) h0 : a = b = c = d = e.
