CHEM 104 Study Guide - Ammonia, Lewis Acids And Bases, Aspirin

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30 Oct 2014
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Note: all arrows are equilibrium arrows: a 0. 10 m solution of lactic acid, ch3chohco2h, has a ph of 2. 43. Ka = 1. 4*10-4: what is the ph of the solution that results from mixing 25 ml 0. 016 m nh3 and 25 ml. Ka=5. 6*10-10: write the reaction of nh3 with hcl. Nh3 + h3o+ nh4: write the reaction of the products of (a) with water. + + h2o nh3 + h3o: find the concentration of product in solution upon mixing. M1v1 = m2v2 (0. 016 m)(25 ml) = m2(50 ml) M2 = 0. 0080 m: use an ice table to solve for ph. Ka = x2/0. 0080-x = 5. 6*10-10 x=2. 1*10-6 m ph=5. 67: find ph and poh of a 0. 25 m solution of ch3nh2 which has kb = 4. 2*10-4. Kb = x2/0. 25-x = 4. 2*10-4 x=0. 010 m poh=1. 99 ph= 12. 01. + + oh: aspirin (c9h8o4) has ka = 3. 27*10-4. 2(0. 345)/0. 225 l * 1 mol/180. 2 g = 0. 0160 m aspirin.

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