MATH 205 Midterm: MATH 205 Louisville Practice Exam 3 150410 Solution
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For full credit show all of your work (legibly! Algebraic and trigonometric simpli cation of answers is generally unnecessary: (17 points) answer the following questions: (a) (8 points) find the general antiderivative of g(x) = x3+3x+2 x2 5 1 x2 + csc x cot x. The rst term requires some cleanup; we may rewrite this expression as g(x) = x + 3x 1 + 2x 2 . + csc x cot x and then antidi erentiate term=by=term to nd that. 2 x + 3 ln|x| 2x 1 5 arcsin x csc x + c (b) (9 points) given that f (2) = 0 and f (t) = t3 16 t3 , nd a formula for f (t). They want to ll it as full as possible with machines, but regulations require 10 feet of open oor space along each wall, and 15 feet of open oor space along the loading dock. 10 y y 25 y 25.
