ANTH 2 Midterm: Solution to Practice Problems Midterm 1 Math 3 Precalculus-1
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) 1, ( b) domain of g(x): set of all real numbers, x 0 or , 0. ) 0, ( c) domains of ( f + g)(x), ( f g)(x), ( f g)(x) : Set of all real numbers, x 0, x 1 or , 0. ) 1, ( d) since g(x) 0 for any real x, the domain of f g (x) is the same as the answer in part (c). e) domain of ( f ! g)(x) = f (g(x)) is the set of x values that are the domain of g(x) which also makes sense for the domain f(x). So the domain of ( f ! g)(x) = f (g(x)) is the set of real numbers, x 0, x 2. Similarly, domain of (g ! f )(x) = g( f (x)) is the set of x values that are the domain of f(x) which also makes sense for the domain g(x).
