MATH 126 Midterm: MATH 126 UW Midterm 1 Fall 09taggartExIans
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Math 126 exam i hints and answers. Autumn 2009: hint: normal vectors of the given planes are n1 = 3, 2, 1 and n2 = 2, 1, 3 . The direction vector for the line of intersection is orthogonal to both of these normal vectors. So, you may take as the direction vector for the line, the vector v = n1 n2 = 5, 11, 7 . The line of intersection pierces the xy-plane at the point (1, 1, 0). Answer: parametric equations for the line of intersection are: x = 1 + 5t, y = 1 + 11t, z = 7t. Other answers are possible: hint: the direction vector for the line is a = 2, 3, 1 . A point on the line is p0(1, 0, 2). The vector from p0 to the point (3, 4, 3) is b = 2, 4, 5 .
