MAT 127 Midterm: mt1s08sol

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April 19, 2016: (20 pts) compute the following. (a) z 4. We need to convert the limits: when x = 0, u = 4. Let: u = arctan x dv = dx du = To solve the last integral, let u = 1 + x2, du = 2x dx. 2 ln|1 + x2| + c: (20 pts) (a) compute z esin(x) cos(x)dx. We know that the average value of f (x) on [a, b] is. Easy solution: the function f (x) = x cos(x) is an odd function, i. e. f ( x) = f (x). Therefore its integral over any symmetric interval (e. g. [ , ]) vanishes. Hard solution: if you fail to notice the symmetry, then you have to compute the integral. Use ibp: u = x dv = cos(x)dx du = dx v = sin(x). fave = Once again, the integral of sin(x) vanishes by symmetry since sin(x) is odd.

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