MATH 241 Midterm: MATH241_ROSENBERG-J_FALL2005_0111_MID_SOL_1

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10 Jan 2019
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Friday, october 28, 2005: (25 points, divided as indicated) (a) (15 points) find the tangent plane to the surface x sin y cos z + exy + z2 = 1 at the point (1, 0, 0). Let f (x, y, z) = x sin y cos z + exy + z2; then. F = (sin y cos z + yexy, x cos y cos z + xexy, x sin y sin z + 2z). Thus f (1, 0, 0) = (0, 2, 0), and this must be normal to the level surface of f through the point (1, 0, 0). The partial derivatives are f / x = 3x2 + 3y, f / y = 3x + y. Thus the equations for a critical point are. 3x2 + 3y = 0 (or x2 + y = 0) and 3x + y = 0. So y = 3x, x2 3x = 0, x(x 3) = 0.

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