MATH 141 Study Guide - Quiz Guide: Absolute Convergence, Alternating Series, Ratio Test

Section: Online Paper Homework Assignment 7 Determine whether the following series converge absolutely. converge conditionally, or diverge k+3 Part (A): Define the absolute series Σ Test it for convergence or divergence Part (B): If the above series does not converge, then test the original given series using the Alternating Series Test: Conclusion: (Please circle your answer and fill in the blank). Σ(-1)'r-converges conditionally by the Σ(-1)'r-1 converges absolutely by the Σ(-1)' k,-| diverges by the Test. k2 +3 Test k +3 Test.

Math 1312 Practice Exam 2 There will be 6 or 7 problems on the actual test. All of them will be similar to the problems shown here. (Note that in the given solutions, all work is not shown) 1) Find a formula for an,n 1. 1-49-1625 2 3'4 5 6 2) Find the exact sum of the series, if possible, 135m Determine if the following series converge or diverge. You need to clearly state which test you are using, and show all of your work. 3) c) 1(2n):(n-1) e) f) Σ-1co.nn) Σ-=ínti (use Divergence Test, lim-loso series diverges) 4) Determine whether the series is absolutely convergent, conditionally convergent, or divergent. 3n 5) Find an expression for the general term of the following series. Give the starting value for the index (x-2)2-2) 2))2)10 2 16 32 6) Use the ratio test to find the radius of convergence of the power series.

hw10: Problem 13 10 Prev Up Next ail (1 pt) For each of the series below select the letter from A to C that best applies and the letter from D to K that best applies. A possible answer is AF, for example. roblems om 1 em 2 om 3 om 4 om 5 A. The series is absolutely convergent B. The series converges, but not absolutely. C. The series diverges. D. The alternating series test shows the series converges E. The series is a p-series F The series is a geometrio series G. We can decide whether this series converges by comparison with a p-series. H. We can decido whether this series converges by comparison with a geometrio series I. Partial sums of the series telescope. J. The terms of the series do not have limit zero. K. None of the above reasons applies to the convergence or divergence of the series m 7 m 8 m 9 m 10 m 11 m 12 m 13 m 14 m 15 n 16 m 17 n 18 cos(n) sl (2n+6)! 6+sin(n) n 20 n 21 n 22 n 23 7 log(7 + m) Note: You can earn partial credit on this problom.