CHEM 131 Midterm: Exam 2 No Solutions Fall 2004

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Show your work as partial credit will be given. Here is a list of possibly useful formulae: e bx2 x2e bx2 dx = q /b. N ln(n) n j(x) = d dc dx dc dt dc dt. = d dc dr j(r) = d dj dx d2c dx2 q kbt ec! j = d dc dx c(r) = P v = nkbt = nrt ln(c2/c1) = q v /kbt. 1 (1) (2) (3) (4) (5) (6) (7) (8) (9) (10) (11) (12) (13) (14) (15) (16) (17) (18) (19) (20) (21) (22) (23) (24) (25) (26) (27) (28) (29) (30) (31) (32) (33) (34) (35) ds de. F = e t s = kbt ln z. G = e + pv t s p. T ds dv p = ckbt ds dn. Z = xi dx2 = 2 a jq,r + c d2v dv dt ! i ) + jp ump ji = gi zie.

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