MATH 251 Midterm: MATH 304 TAMU MidtermExam1 Solution

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31 Jan 2019
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Math 304 linear algebra sections 505 and 506. Start with the one, which you consider the easiest one. You can use scratch paper to think about your solution. Show all your work neatly and concisely and box your nal answer. You will be graded not merely on the nal answer, but also on the quality and correctness of the work leading up to it. 3 det(a) = 2(9 0) + 5(0 3) = 18 15 = 3. After two row changes b is a diagonal matrix with exactly the non-zero entries on the diagonal. The rst and the last row of c are equal, thus det(c) = 0. det(b) = 1 3 4 2 1 = 24. Also write down its reduced row echelon form. The row echelon form of a nonsingular n n matrix is the identity matrix. Hence, a must be zero to make the matrix consistent.