MATH 152 Midterm: MATH 152 TAMU 2015a X2ABsol
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Fri, 27/mar: (c) as n , an = c(cid:13)2015 art belmonte ( 1)n n. 2n + 5 n 0. an = ln: (d) completely factor the denominator to choose the correct answer; denom = (x + 3)3 (x 3)(cid:0)x2 + 16(cid:1), (b) as n , (3n + 5)2. 14 : (b) long divide the integrand; integrate term by term. c q1 + (dx/dy)2 dy or, (a) the arc length is l =r d. 5 6= 0, the series : (e) since 3 sin2 x. 5 e n 1 diverges by the test for divergence: (a) since n=1. 5 e n: (e) let x = 3 sin . Hence (27, 9) correspond to t = 2 and t = 3, respectively: (d) with x = t 3 and y = t 2, the points (8, 4) and. 3 sec2 d , which equals: (d) now.
