MATH 151 Midterm: MATH 151 TAMU Y2010 2010c Exam 2a Solutions
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Math 151 fall 2010 exam ii: d. an object is moving according to the equation. = lim t 0(cid:18) t sin(2t)(cid:19)3 s(t) = t3 9t2 + 15t + 8. The object is moving in the negative direction when v(t) < 0. Now, v(t) = s (t) = 3t2 18t + 15 = 3(t 5)(t 1). Solve v(t) < 0 yields 1 < t < 5. x x 4. Find the slope of the tangent line to the curve x x 4. 3(cid:19) y3 xy = 2x + 4 at the point (1, 2). Solve for yields dx y x dy dx dy dx. Substitute x = 1 and y = 2 gives us a dy dx. Find the linear approximation, l(x), of f (x) = x2 + 9 at x = 4. The linear approximation for f (x) at x = 4 is.
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