CSE 215 Quiz: Recitation 3
12 Mar 2017
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N = 3, we get 5 which is prime. N , 2n2 - 5n + 2 is prime. X, n is odd, then (n-1)/2 is odd. N,m e n, 2m + n is odd. => m is odd and n is odd. 2m + n = 5 is odd but m is even. We use n = 5 where the formula gets us 2 which is even. A - b = 2k - 2q - 1. K - q - 1 is also in z therefore this statement is true. This means that b = a2 for some a in n. Prove that the sum of 4 consecutive integers is one less than a perfect square. Using k is an integer k(k+1)(k+2)(k+3) + 1 = a2. We know that a^2 - 1 can also be written as (a-1)(a+1) To help us solve, we will multiply k with k+3 and k+1 and k+2.
