MATH 230 Midterm: Test 2 review solutions

24 views8 pages

turquoisegnu128

15 Feb 2019

School

Northwestern University

Department

Mathematics

Course

MATH 230

Professor

All

For unlimited access to Study Guides, a Grade+ subscription is required.

Document Summary

1 (a) and (i) (b) and (iii) (c) and (ii) (d) and (vi) (e) and (iv) (f) and (v: first of all, note that r (t) = h2 cos t, 3, 2 sin ti. The velocity is given by the speed is equal to v(t) = r (t) = h6 cos(3t), 8, 6 sin(3t)i , |v(t)| =q36 cos2(3t) + 64 + 36 sin2(3t) = 36 + 64 = 10 and the acceleration is given by a(t) = v (t) = h 18 sin(3t), 0, 18 cos(3t)i . To nd the total distance travelled, we need only integrate speed: 1: since the acceleration vector is a(t) = hcos t, sin t, gi, the velocity vector is for some constant vector b. This makes the position vector r(t) =(cid:28) cos t, 5t sin t, gt2. In particular, the object"s position when t = /2 is and its position when t = is r( /2) =(cid:28)1,

Related Questions

Problem 4 Circle your answer. a) (6 points) If f(x) = 2x + 3x2 - 361 + 5, then the tangent line to the graph y= f(x) is horizontal when i) 1 = -2,3 ii) I = 2,-3 iii) r = 0 iv) not listed b) [6 points] Suppose Given h(x) = f(g(T)), where g(2) = 3, g'(2) = 7, f'(2) = -1 and 1'(3) = -2. Then h'(2) is equal to i) - 1 ii) -2 iii) - 14 iv) not listed (x+3)(1 - 1)3 c) (6 points) The function f(1) == (x2 - 2x + 1)(x + 3) wa has vertical asymptotes at i) x = -3,0 ii) = -3,0,1 iii) x = 0,1 iv) not listed d) (6 points] The solution to the initial value problem v'(x) = 473 – cos(x) +e", y(0) = 3 is i) y(x) = x + sin(x) + e* + 2 ii) y(I) = x4 – sin(x) +et+2 iii) y(x) = 2* – sin(1) + et + 3 iv) not listed

Calc 4 review! I need help with any of all of them!

2. (20 pts) An object begins moving along a vertical line at time t = Os and stops at time t = 6 s. Its height above the ground at time t is given by h(t) in the provided graph, where h is measured in meters. Use the graph to answer the following questions. on 0 (a) Compute the average velocity of the object on the time interval [0,6). Show your work. N 1 2 3 4 5 6 (b) Circle the choice that best describes the shape of the graph on the time interval (5,6). i. increasing and concave up ii. increasing and concave down iii. decreasing and concave up iv. decreasing and concave down (c) At what time is the object farthest away from the ground? What is the velocity at that time? time= velocity= (d) The maximum velocity attained on (0,6) occurs at one of the following times. Circle the correct choice. i. ls ii. 2 s iii. 3s iv. 4s v. 5s (e) Estimate the value of the maximum velocity attained. The value is an integer. (f) Let v(t) be the velocity at time t. Circle the greatest value amongst the following choices. i. v(2.5) ii. (2.6) ii. v(2.7) iv. v(2.8) V. (2.9) (8) List the time interval(s) on which the velocity is increasing. Use integer endpoints. (h) The maximum speed attained on (0,6) occurs at one of the following times. Circle the correct choice. i. ls ii. 2s iii. 35 iv. 4s v. 5s

MATH 230 Midterm: Test 2 review solutions

Document Summary

Get access

Related textbook solutions

Calculus

Single Variable Calculus: Early Transcendentals

CALCULUS:EARLY TRANSCENDENTALS

Related Documents

MATH 230 Midterm: Test 2 review

MATH 230 Final: Final winter 2014 solutions

MATH 230 Midterm: Test 1 spring 2014

Related Questions