CHEM 1202 : Exam 1 Review

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15 Mar 2019
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Equilibirum constant k & reaction quotient q aa + bb cc + cd. P(h2o) = 0. 600 atm; p(co) = 1. 525 atm; p(h2) = 0. 805 atm. Kp = 2. 6: h2s(g) + i2(g) 2 hi(g) + s(s) P(i2) = 0. 461atm; p(h2s) = 0. 050 atm; p(hi) = 9 atm. Kp = 0. 0023: cocl2(g) co(g) + cl2(g) Kp = 6. 26 x 10-22 (at 298 k) Kp = 7. 7 x 1024 (at 298 k) Kc = 3. 7 x 108 (at 298 k) Kc = 4. 1 x 10-31 (at 298 k) Kf = k1 x k2: calculate the equilibrium constant for new reactions with the given informations, given: 6 clo3(g) 2 clf(g) + 4 clo(g) + 7 o2(g) + 2 f2(g) Find: 13 clf(g) + 23 clo(g) + 76 o2(g) + 13 f2(g) clo3(g) Kf = : given: xef6(g) + h2o(g) xeof4(g) + 2hf(g) Find: xeo4(g) + 2hf(g) xeo3f2(g) + h2o(g: given: 2 geo(g) + w2o6(g) 2 gewo4(g)