MAA 3200 Midterm: MAA 3200 FIU Exam 113k

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15 Feb 2019
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Prof. s. hudson: [20 pts] answer true or false. (p q) p q ( k z, 2k = 8) ( k z, 5k = 25) K z, (2k = 8 5k = 25) ((p q) p ) q is a contradiction. !x r, (x 1)(x 3)(x 5) = 0 |x 2| < 2. If n 7 is an integer, then there are positive integers k, j so that n = 2k + 3j. There is a set that is a member of every set. In the real numbers, x, y, w, wxy < w2. If a is a proper subset of then a = {17}: [15 pts] let a, b be sets with p (a b) = p (a) p (b) (as usual, p refers to the power set). Prove that a b or b a: [15 pts] prove that for all integers n 1, The next few problems are intended to be fairly easy and short.

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