APPM 1360 Midterm: appm1360summer2017exam1_0

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31 Jan 2019
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Summer 2017: (30 pts) evaluate the following integrals, z x2 + 4x + 1 x3 + x2 dx. 0 dt (1 t2)5/2: z 9. X x 1 dx: z (cid:0)tan4 x sec4 x(cid:1) dx, z x2. If the integral in part (a) converges, nd its value: z 1. 0 x ln x4 dx: z . Midpoint rule mn = x [f ( x1) + f ( x2) + + f ( xn)] where x = b a n and xi = 1. 2 [f (x0) + 2f (x1) + 2f (x2) + + 2f (xn 1) + f (xn)] where x = b a n.

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