PHYS UN1402 Study Guide - Quiz Guide: Electric Potential, Ds 3
27 Apr 2020
School
Department
Course
Professor
Document Summary
I"d like to remark on a few points which i muddied during class so everyone is on the same page. The proper de nition of the electric potential change: V = v (r2) v (r1) = z r2 r1. The ~ds vector is always taken to be in the positive direction. We take care of our path via the bounds of the integral. So the lower bound = the initial point, and the upper bound = the nal point. We know using gauss" law that the electric field outside: For this part of the question, upon thinking about this after class a little, i realized that i made a mistake: The electric field does not need to be. There is a simple physical reason behind it, and it is that if the potential was discontinuous, it would give rise to an in nite electric eld at the point of the discontinuity and hence an in nite force.
