MATH 0180 Midterm: MATH 180 Brown Exam m180s10b

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31 Jan 2019
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Math 180 solution to quiz #10b: cole. Let s be the surface {(x, y, z) : 5(x2 + y2) = z2 + 1, 2 z 2} with unit normal vector n pointing away from the z-axis. Solution: (a) div f = y2 + 0 + y2 = 0. (b) put h(x, y, z) = 5(x2 + y2) z2 1. Since h = 0 on s, we see that h = 10x, 10y, 2z is normal to s. since h points away from the z-axis, we conclude that n points in the same direction as h along s. (use the symbol t to denote the. Let t = {(x, y, z) : h(x, y, z) 0, 2 z 2}. boundary of t . ) Note that t = s s1 s2 where s1 = {(x, y, 2) : x2 + y2 1} and. S2 = {(x, y, 2) : x2 + y2 1}.

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