CHM ENG 140 Study Guide - Midterm Guide: Ideal Gas, Phase Diagram, Lead

30 views5 pages

Document Summary

*credit was also given for using tc=647k (value given in book) z=0. 625. Compressibility chart gives a value closer to ideal gas than steam table. 0. 2(100 kg/hr) + 0. 5*mw,w1 = mw,w1 mw,w1= 40 kg/hr. 0. 8(100 kg/hr) + 0. 5*ma,w1 = ma,c + ma,w1 ma,w1= 160 kg/hr 2ma,c. Using k: overall mass fractions: xa=80/200=0. 4 xm=100/200=0. 5 xw=0. 1. From tertiary phase diagram, two phases are formed, where one is mibk rich and one is h2o rich. K=0. 4/0. 29=1. 4 (compared to 1. 72), so less acetone will be extracted: 1) 2+3-2=3 intensive variables. Since t and p are specified, only 1 mass fraction must be specified: if one mass fraction is specified, one point on the semi-circle on the tertiary phase diagram is known. Problem 4 solution: a)raoult"s law: xb*p*(benzene, 75c)=yb*p (1-xb)*p*(n-hexane, 75c)=(1-yb)*p xb*647. 75=yb*760 (1-xb)*921. 343=(1-yb)*760 yb=0. 50, xb=0. 59 yh=0. 50, xh=0. 41. Benzene: 54. 5 mol/s=0. 50*mv+0. 59*ml n-hexane: 45. 5 mol/s=0. 50*mv+0. 41*ml mv=50 mol/s ml=50 mol/s a) hhex,v=25 mol/s * [(68. 74-30 c)*0. 2163 kj/mol + 28. 85 kj/mol + (75-68. 74.

Get access

Grade+
$40 USD/m
Billed monthly
Grade+
Homework Help
Study Guides
Textbook Solutions
Class Notes
Textbook Notes
Booster Class
10 Verified Answers

Related Documents